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2 years ago

7

Simplify (5y-6)-(4-7y)

1 answer:

kolbaska11 [484]2 years ago

8 0

The answer is 12 − 10

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Find the solution set.

kow [346]

Answer: 5, -5

Step-by-step explanation:

There are only 2 square roots of 25: plus and minus 5.

7 0

3 years ago

at the start of the shift your part counter reads 250 at the end of the shift the part counter reads 1075 how many parts did you

Luden [163]

This can be mathematically expressed to
250 + X = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825

You produced 825 parts in the middle of the shift.

5 0

3 years ago

Hurry 50 points for correct answer

Ad libitum [116K]

Answer: <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

Step-by-step explanation:

The equation $x=\sqrt{6x+7}$ can be solved by squaring both sides:

$x^2 = 6x + 7\\\\x^2 - 6x - 7 = 0\\\\(x-7)(x+1) = 0$

We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:

$1 = \sqrt{-1}\\ 7 = \sqrt{49}$

The square root of 49 equals 7, but the square root of -1 is an imaginary number.

The correct choice is <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

4 0

3 years ago

An obtuse triangle has angle measurements of 100°, 60°, and 20°. If the longest side of this triangle is 20 feet,

san4es73 [151]

Answer:

20/sin 100=x/s 20

x=(20s 20)/100

x=6.95 feet

The answer is 6.95 feet

Step-by-step explanation:

5 0

3 years ago

Find two complex numbers that have a sum of i10 a different of -4and a product of -29

lianna [129]

<h2>-2+5i and 2+5i</h2>

Step-by-step explanation:

Let the complex numbers be $a+ib\textrm{ and }c+id$ .

Given, sum is $10i$ , difference is $-4$ and product is $-29$ .

$(a+c)+i(b+d)=10i$ ⇒ $a+c=0,b+d=10$

$(a-c)+i(b-d)=-4$ ⇒ $a-c=-4,b-d=0$

$a=-2,c=2,b=5,d=5$

$(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29$

Hence, all three equations are consistent yielding the complex numbers $-2+5i\textrm{ and }2+5i$ .

8 0

3 years ago