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2 years ago

Help im on a meeting this need to be done

Mathematics

1 answer:

Trava [24]2 years ago

8 0

Answer:

Step-by-step explanation:

two quarters=half

4/8=1/2

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The answer is sin because x is opposite of the angle and you have the hypotenuse.

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3 years ago

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The tape diagram below represents 100% percent.

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The shaded area is 75%

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3 years ago

Solving Rational equations. LCD method. Show work. Image attached.

Ugo [173]

Answer:

$k=\frac{1}{2}$

Step-by-step explanation:

The given rational equation is

$\frac{5k}{k+2}+\frac{2}{k}=5$

The Least Common Denominator is

$k(k+2)$

Multiply each term by the LCD.

$k(k+2)\times \frac{5k}{k+2}+k(k+2)\times \frac{2}{k}=5k(k+2)$

Simplify;

$k\times \frac{5k}{1}+(k+2)\times \frac{2}{1}=5k(k+2)$

$\Rightarrow k(5k)+2(k+2)=5k(k+2)$

Expand;

$\Rightarrow 5k^2+2k+4=5k^2+10k$

Group similar terms;

$\Rightarrow 5k^2-5k^2+2k-10k=-4$

$\Rightarrow -8k=-4$

Divide by -8.

$k=\frac{1}{2}$

5 0

3 years ago

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

aliina [53]

Answer: B. H(t) = -6.9(t - 2.3)² + 112

<u>Step-by-step explanation:</u>

The vertex form of a quadratic equation is: y = a(x - h)² + k

where (h, k) is the vertex ⇒ k is the maximum height

the distance traveled is when y = 0 ⇒ $x=\sqrt{\dfrac{-k}{a}}+h$

Given: H(t) = -7.1(t - 2.3)² + 98

maximum height (k) = 98 feet

distance traveled (x) = $\sqrt{\dfrac{-98}{-7.1}}+2.3$ = 6.02 seconds

A) H(t) = -7.5(t - 2.2)² + 112

maximum height (k) = 112 feet

distance traveled (x) = $\sqrt{\dfrac{-112}{-7.5}}+2.2$ = 6.06 seconds

B) H(t) = -6.9(t - 2.3)² + 112

maximum height (k) = 112 feet

distance traveled (x) = $\sqrt{\dfrac{-112}{-6.9}}+2.3$ = 6.33 seconds

C) H(t) = -6.9(t - 2.4)² + 95

maximum height (k) = 95 feet

This has a lower height than the given equation.

D) H(t) = -7.5(t - 2.3)² + 95

maximum height (k) = 95 feet

This has a lower height than the given equation.

Both options A and B travel higher and stay in the air longer than last year's winner, however option B stays in the air longer than option A.

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3 years ago

A team of runners is needed ti run 1/4- mile relay race.if each runner must run 1/16 mile,how many runners will be needed

Pavel [41]

If each runner must run 1/16 of 1/4 mile then you need 4 runners because four runners makes 4/16 points. this number is equivalent to 1/4 which proves this statement true

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3 years ago

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