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LUCKY_DIMON [66]
3 years ago
7

Noah starts with 0 and then adds the number 5 four times. Diego starts with 1 and then multiplies by the number 5 four times. Fo

r each expression, decide whether it is equal to Noah’s result, Diego’s result, or neither.
4 ⋅ 5


4 + 5


4^5


5^4
Mathematics
1 answer:
Fittoniya [83]3 years ago
4 0
4 • 5 is Noah and 5^4 is Diego
You might be interested in
Need some help with this question!
Veronika [31]
1. solve for x in first to just find nterms of y

x=12-y
sub that for x in other one
first divide that one by 2 to make it easier
2x-y=18
2(12-y)-y=18
24-2y-y=18
24-3y=18
minus 24 both sides
-3y=-6
divide -3
y=2

D is answer




2.
find intersection of x+y=5 and -2x+3y=6
or easiers, just test the intersections
wait, they all intersect in the same place
this is super easy
pick ANY point that is in that reigon and see if it is true

A, if we pick lets say (5,5)
that is false for x+y<5
not A

B
pick (10,0)
false for first one
not B

C
pick (0,0)
true for first
false for 2nd
not C


D. pick (-10,0)
true for first
true for 2nd


answer is D


answer is D for both questions
6 0
3 years ago
Write 102,800,000 in scientific notation
Fudgin [204]

Answer:

1.028 × 10^8

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is
Anna35 [415]

Answer:

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

         Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = average gestation period = 270 days

            \sigma = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X \leq 261)

         P(X < 279) = P( \frac{ X - \mu}{\sigma} < \frac{279-270}{9} ) = P(Z < 1) = 0.84134

         P(X \leq 261) = P( \frac{ X - \mu}{\sigma} \leq \frac{261-270}{9} ) = P(Z \leq -1) = 1 - P(Z < 1)

                                                           = 1 - 0.84134 = 0.15866

<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

3 0
3 years ago
Easy question easy points yall :p
yarga [219]

Answer:

+or- 8

Step-by-step explanation:

take the square root of 64

8 0
3 years ago
Read 2 more answers
If it takes 8 inches of ribbon to make a bow,how many bows can be made from 3 feet of ribbon (1 foot = 12 inches)? Will any ribb
Aloiza [94]

First, find out how much ribbon there is.

3 x 12 = 36

Now, see how many times you can divde that by 8.

36 can only be divided by 8 four times, and there would be 4 inches of ribbon left.

So, you would be able to make 4 bows, with 4 inches of ribbon remaining.

8 0
3 years ago
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