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Zinaida [17]
3 years ago
5

April and Sanjay are both using tools to simulate the probability that a family with three children will have exactly one girl.

April is using a coin, with tails up representing a boy and heads up representing a girl. She flipped the coin three times. Sanjay rolled a number cube three times with odd numbers representing a boy and even numbers representing a girl.
Explain the differences in the theoretical probability and the experimental probability.
Mathematics
1 answer:
Oxana [17]3 years ago
6 0

Answer:

Theoretical probability is what we expect to happen, where experimental probability is what actually happens when we try it out. The probability is still calculated the same way, using the number of possible ways an outcome can occur divided by the total number of outcomes. As more trials are conducted, the experimental probability generally gets closer to the theoretical probability.

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Answer:

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(Just multiply)

6 0
3 years ago
Read 2 more answers
Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un
erica [24]
At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1 - r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &1013\\&#10;I=\textit{initial amount}\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &0\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I

so, the inital amount is 1013, when t = 0,

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1- r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\to &1013\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &t\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.


7 0
3 years ago
What is the integer for 2°f above zero
Illusion [34]
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5 0
3 years ago
Evaluate x+x-x for x=4
Dafna1 [17]
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3 0
3 years ago
A rectangle is 2m long. It’s diagonal is 3m long. Work out the width of the rectangle, to the nearest cm
Marizza181 [45]

Answer:

To the nearest cm

Width of the rectangle = 224cm

Step-by-step explanation:

Imagine a rectangle shape,

both opposite sides are equal, ie both lengths are equal and also applicable to the widths

Length is 2m

It's diagonal is 3m

The diagonal is a line that crosses from one length of a side to the other slantly, ie from one edge to the other, dividing the rectangle into two right angled triangles

The longest line will be the diagonal which is 3m

And the base length will be the length which is 2m

The width is what we are looking for which is represented with x

To solve this problem, we use Pythagoras' rule

x^2 = a^2 + b^2

Let x be diagonal side

a be length

b be the unknown width

Inserting into the formula

x^2 = a^2 + b^2

3^2 = 2^2 + b^2

9 = 4 + b^2

9 - 4 = b^2

5 = b^2

Square root of 5

b = 2.24m

The width = 2.24m

According to the question, we are asked to give the answer in nearest cm

Since 1cm = 0.01m

x cm = 2.24m

Then we cross multiply

1cm * 2.24m = xcm * 0.01m

x = 2.24 / 0.01

x = 224cm

5 0
3 years ago
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