Question

Please answer quickly I will give brainliest- Kelsey has a list of possible functions. Pick one of the g(x) functions below and then describe to Kelsey the key features of g(x), including the end behavior, y-intercept, and zeros.
I'm using this one:

g(x) = (x + 3)(x + 2)(x − 3)

Answer 1

Answer:

1. Behavior

The g(x) is large and positive when x is large and positive;

The g(x) is large and negative when x is large and negative.

2. y-intercept= -18

3. The zeros are: -3, -2 and 3

Step-by-step explanation:

1. End behavior:

To find this you have to know the leading coefficient of the variable with the highest degree, and whether the degree is even or odd.  

(x + 3) = x positive, coefficient 1

(x + 2) = x positive, coefficient 1

(x − 3)=  x positive, coefficient 1

The coefficient is 1*1*1= 1 = positive

There are 3 x, so it will be x^3= odd

The behavior for odd and positive will be:

g(x) is + ∞ when x=>+∞

g(x) is -∞ when x=>-∞

or

The g(x) is large and positive when x is large and positive;

The g(x) is large and negative when x is large and negative.

2. Y-intercept

The y-intercept is the value of y when the graph touches the y-axis. The y-axis is located at x=0, so to find the y-intercept you need to put x=0 on the graph function. Some graphs can have two y-intercepts but the graph on the question only has one. The calculation will be:

y-intercept = g(0)= (0+3)(0+2)(0-3)

y-intercept = 3*2*-3

y-intercept= -18

3. Zeros

The zeros mean the value of x that will result as g(x) as zero. At this coordinate, the graph will touch the x-axis since g(0) is located on the x-axis. That is why this coordinate also called an x-intercept. The function is expressed as the product of three things. If any of them is 0, then the result will be 0. So we have 3 zeros

$x_{1}$+3=0

$x_{1}$=-3

$x_{2}$ +2=0

$x_{2}$=-2

$x_{3}$-3=0

$x_{3}$=3

The zeros are: -3, -2 and 3