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quester [9]
3 years ago
7

The product of 8 and x plus the quotient of y and 7. answer choices are (8 + x)/(7 + y) (8x) + (y/7) (8 + x)(y/7)

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer: (8x) + (y/7)

The word 'product' means multiplication and the word 'quotient' means division. Only (8x) + (y/7) multiplies 8 and x while diving y and 7.

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What is the area of the figure?
Vikentia [17]


1) Striangle = 1/2 * (12-8) * 4 = 1/2 * 4 * 4 = 8 km^2

2) Srectangle = 4 * 8 = 32 km^2

3) Sfigure = 8 + 32 = 40 km^2

Number C

4 0
4 years ago
What function corresponds to the ordered pairs shown in the table?
Anettt [7]

well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{11}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{11}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}}\implies \cfrac{11+7}{3+3}\implies \cfrac{18}{6}\implies 3

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}(x-\stackrel{x_1}{(-3)}) \\\\\\ y+7=3(x+3)\implies y+7=3x+9\implies y = 3x+2

6 0
3 years ago
Combining like terms with negative coefficients
almond37 [142]
-3z - z = -3z - 1z = -4z
6 0
3 years ago
Help me RQ i need the answer i give out brainlist and 5.0 if ur correct !!!
Slav-nsk [51]

Answer:

<h2>C) the length of each shape will alternate between even and odd numbers</h2>

Step-by-step explanation:

the rest are incorrect

7 0
3 years ago
Hey can anyone pls answer these math problems!!
Zepler [3.9K]

Answer:

1={5 and 3} 2={0} 3={0.209 and 4.791} 4={-3 and 4} 5={1 and 9} 6={-4.303 and -0.697}

Step-by-step explanation:

Your probably confused on what a, b, and c means.

The problems are written like this.

ax^2+bx+c=0

That formula finds the zeros.

For example 1:

x^2-8x+15=0\\ax^2-bx-c\\a=1\\b=-8\\c=15

Then use the formula

x=\frac{-b+-\sqrt{b^2-4ac} }{2a} \\\\x=\frac{-(-8)+-\sqrt{-8^2-4(1)(15)} }{2} \\x=\frac{8+-\sqrt{64-60} }{2} \\\\x=\frac{8+-2}{2}\\

If plus then 5, if minus then 3

CHECK:

x^2-8x+15=0\\5^2-8(5)+15=0\\25-40+15=0\\0=0\\3^2-8(3)+15=0\\9-24+15=0\\0=0

Hope this helps you understand how to do this by yourself.  Now to do the rest ;-;

5 0
2 years ago
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