First, let me do the Mathematical part of that, and then I shall explain the theory behind it.
Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.
Multiply 513 with 6 first.
513
x46
--------------------------
18 (as 6*3 = 18)
60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
120 (as 40*3 = 120; since 4 is at the tenth place, so 4*10=40)
400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)
Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.
Check: If we check the multiplication result by using the calculator, we would get the same result (23598).
Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.
A.) the slope is -3 this is because you needed to distribute first making -3 combine with x making it the slope,, the equation end product would be y=-3x-46
Answer:
9x?lax+1)-1(2x+i)=0 p²-8p+4=0. (2x+1)(9x2-1)=0. 0-81764-40X4). (2x+1)(3x +1 (3x-1)=0 x= -1/2 x=-1/2 x=1/3. P= 843-4+213 x={-1/23 - 1 3 3 3 3 3. 4. Let 'n(x)=x2-Ox and g(x)=2x-7. Find all values of x, for which h(x) = g(x).
Step-by-step explanation:
Sheet #14-1. Quadratic Equations: Solving in Factored form. Algebra Common Core. MOVING WORDS. ... X+4 = 0 1 x +9=0 nr 3-01n-10-0 h=0 h-14=0. -4 -4 -9 -9. -3-3 tiu to. +14 114. X = -4 x=-9 n=-31 n =10 h = 14.
3:4:5 you just divide all of them by 10