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stiv31 [10]
2 years ago
13

To prove that ΔAED ˜ ΔACB by SAS, Jose shows that StartFraction A E Over A C EndFraction = StartFraction A D Over A B EndFractio

n.
Triangle A E D is shown. Line segment B C is drawn from side A D to A E to form triangle A C B.

Jose also has to state that
Mathematics
1 answer:
stich3 [128]2 years ago
7 0

The other equality which must be stated by Jose is that angles BAC and BAE are congruent and their measures are equal.

<h3>What other congruence statements must Jose state?</h3>

It follows from the task content that Jose is trying to prove the congruence of both triangles by means of the Side-Angle-Side congruence theorem.

It therefore follows that since, Jose has identified that the ratio of corresponding sides are equal as indicated in the task content, the equality which Jose has to state is the angle congruence equality.

Read more on congruence theorem;

brainly.com/question/3168048

#SPJ1

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2 years ago
A detective finds a victim of murder at 9 am. At that time, the temperature of the body is 90.3 degrees F. One hour later, the b
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Answer:

Step-by-step explanation:

Given

at 9 am temperature of the body is 90.3^{\circ}F

1 hr later temperature 89^{\circ}F

Temperature of room T=68^{\circ}F

According to newtons law

\frac{\mathrm{d} T}{\mathrm{d} t}=-k\left ( T-T_{room}\right )

\frac{\mathrm{d} T}{\mathrm{d} t}=-k\left ( T-68\right )

\frac{dT}{T-68}=-kdt

Integrating

=\int \frac{dT}{T-68}=-kdt

\ln |T-68|=-kt+c

T-68=Ae^{-kt}

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Temperature of Normal human body is T=98.6 ^{\circ}F

98.6-68=e^{-0.06006t}

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