Given
P(1,-3); P'(-3,1)
Q(3,-2);Q'(-2,3)
R(3,-3);R'(-3,3)
S(2,-4);S'(-4,2)
By observing the relationship between P and P', Q and Q',.... we note that
(x,y)->(y,x) which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
Sx(x,y)->(x,-y) [ reflection about x-axis ]
R90(x,y)->(-y,x) [ positive rotation of 90 degrees ]
combined or composite transformation
R90. Sx (x,y)-> R90(x,-y) -> (y,x)
Similarly similar composite transformation may be obtained by a reflection about the y-axis, followed by a rotation of -90 (or 270) degrees, as follows:
Sy(x,y)->(-x,y)
R270(x,y)->(y,-x)
=>
R270.Sy(x,y)->R270(-x,y)->(y,x)
So in summary, three ways have been presented to make the required transformation, two of which are composite transformations (sequence).
We have that the slope of the line containing the pair of points f(1) = -6 and f(-7) = -6. is
From the question we are told
Find the slope of the line containing the pair of points f(1) = -6 and f(-7) = -6.
Where Standard form of Equation is
y=mx+c
Generally the equation for the Slope is mathematically given as
Therefore
Therefore
The slope of this line is
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Answer:
n=-0.04761
Step-by-step explanation:
given 
-5=2+
-=2+5
=7
-3=
63n=-3
n=
=-0.04761
n=-0.04761 answer
Answer:
y=3x
Step-by-step explanation:
