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zmey [24]
3 years ago
6

Simplify. (-√7)(-√7)

Mathematics
1 answer:
Savatey [412]3 years ago
5 0

Answer:

<em><u>7</u></em>

Step-by-step explanation:

(-√7)(-√7)

(-\sqrt{7})^2

(\sqrt{7})^2

<em><u>7</u></em>

<em><u /></em>

<em><u>Please Mark As Brainliest</u></em>

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Choose all the fractions that are equivalent to1/7. (Click all that apply.)
Alchen [17]

Answer:

2/14, 4/28, 5/35, 7/70 or just 2/14

Step-by-step explanation:

Multiply both the numerator and denominator of 1/7 by 2, to get 2/14, or 2:14

And multiply the numerator and denominator of 1/7 by 3, to get 3/21, or 3:21. So 2:14 and 3:21 are two ratios that are equal to 1:7.

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Read 2 more answers
If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

By the quadratic formula,

x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2

Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}

Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

3 0
3 years ago
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