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Kipish [7]
3 years ago
14

What is the square footage of a ploygon that is 120 x 100?

Mathematics
1 answer:
viva [34]3 years ago
8 0

Answer:

12000

Step-by-step explanation:

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Find the value of x in the triangle shown below. Help me Geometry question please!!​
Makovka662 [10]
Since this is a isosceles triangle, x would be 50 degrees because 80 plus the two other angles which are equal (50) equals to 180 degrees
8 0
3 years ago
−2(x + 3) = −2(x + 1) − 4.
IrinaVladis [17]

- 2(x + 3) =  - 2(x + 1) - 4 \\  - 2x - 6 =  - 2x - 2 - 4 \\  - 2x =  - 2x \\ x = x

Every x is a solution.

5 0
3 years ago
Hey surveyor is measuring the distance across a small lake. He has set up his transit on one side of the lake 150 feet from a Pi
AleksAgata [21]

Answer: 87 feet

Step-by-step explanation:

The angle between the pilling is 60°

The adjacent side of the right angle is 150

So let the distance between the pilling be y, that is opposite side.

Opposite / adjacent = tan (60°)

y / 150 = tan (60)

y × tan (60°) = 150

Divide both side by tan (60°)

y = 150 / tan (60°)

y = 150 / 1.7321

y = 87 feet

4 0
3 years ago
Which expressions are equivalent to 1.5?
3241004551 [841]

Answer:

B and C

Step-by-step explanation:

We can just solve each to find which expressions are equal to 1.5.

A) 0.15 × 100 = 15

B) 15.0 ÷ 10 = 1.5

C) 0.15 × 10 = 1.5

D) 0.15 ÷ 10 = 0.015

E) 1.5 ÷ 100 = 0.015

From our results, we see that B and C are the only answers that equal 1.5.

6 0
3 years ago
A piston rises to 5 cm and falls to 3 cm in such a way that it returns to the maximal height three times every two seconds. If w
sveticcg [70]

Answer:

(1 cm)cos3πt

Step-by-step explanation:

Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft

where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.

Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations  = 2 s

So, f = 3/2 s =1.5 /s = 1.5 Hz

Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm

h = Acos2πft

= (1 cm)cos2π(1.5Hz)t

= (1 cm)cos3πt

7 0
3 years ago
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