The shortcut is the hypotenuse of a right triangle with legs 6 and 8, so 6²+8²=c²
36+64=c
100=c²
c=10.
so he traveled 6+8+10=24km
Since the distance of MN is 31 and we have a distance of ML
of h -15 and LN of 2h – 8, therefore
ML + LN = h -15 + 2h – 8 = 31
h = 18
substituting the value of h to the expression for LN
obtaining
LN = 2h – 8
LN = 2(18) – 8
LN = 28
Therefore the length of the segment LN is 28 units
