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3 years ago

there are 48 students participating in a debateing tournament each team has 3 students how many debating teams are there

Mathematics

2 answers:

ollegr [7]3 years ago

8 0

48/3

There are 16 debating teams.

babymother [125]3 years ago

3 0

Hello!

Let's divide our 48 students among groups of 3 students below.

48/3=16

Therefore, there are 16 debating teams.

I hope this helps!

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What is the completely factored form of d4 − 81?

lilavasa [31]

For this case we must factor the following expression:

$d ^ 4-81$

Rewriting the expression:

$(d ^ 2) ^ 2-9 ^ 2$

We factor using the formula of the square difference:

$a ^ 2-b ^ 2 = (a + b) (a-b)$

Where:

$a = d ^ 2\\b = 9$

So:

$(d ^ 2 + 9) (d ^ 2-9)$

From the second term we have:

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Finally, the factored expression is:

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Answer:

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6. Fill in the smallest digit to make the number divisible by:

Degger [83]

Answer:

(i) 71640, 321970

(ii) 1143, 47205, 2316

(iii) 1428, 9252, 7212

(iv) 24620, 9100, 6700

(v) 12320, 59016, 46424

Step-by-step explanation:

(i) In order for any number to be divisible by 5, its last digit must be either 0 or 5.

In this case, we should add a last digit, so we opt for 0 without any doubt since it gives a smaller number than 5 as the last digit: 71640 is smaller than 71645, the same way as 321970 is smaller than our second option, 321975.

(ii) If the sum of a number's digits gives a number divisible by 3, then the main number is also divisible by 3.

This means that we have to do some addition:

1_43: 1 + 4 + 3 = 8. Eight is not divisible by 3. But 9 is. So the smallest digit we can add for it to be divisible by three is 1: 1143.

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(iii) Only numbers that are divisible by both 2 and 3 are also divisible by 6.

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4 + 2 + 8 = 14 which is not divisible by 3. But 15 is. So the smallest digit we need is 1: 1428.

9_52: The number will be divisible by 2. And 9 + 5 + 2 = 16 which is not divisible by 3 but 18 is. This means the smallest digit we need is 2: 9252.

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7 + 2 + 1 = 10 which is not divisible by 3 but 12 is. We will then choose to add 2: 7212.

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91__: Here we need to add both of the two last digits, and this should be the easiest example! All numbers that end in 00, meaning they have a round number of hundreds, are divisible by 4! Therefore our option is: 9100.

670_: In this case, we apply the same rule from the last example - and we choose 0: 6700.

(v) In order for a number to be divisible by 8, its last three digits need to be divisible by 8, or it can end in 000, since every number having a round number of thousands is also divisible by 8.

1232_: 320 is divisible by 8 since 8 × 40 gives 320. Therefore, our smallest digit here is 0: 12320.

59_16: If we add a 0 here, the last three digits form the number 016, which is divisible by 8. Our choice is again zero: 59016.

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Answer:

Step-by-step explanation:

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