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Sergeu [11.5K]
3 years ago
7

Solve

Mathematics
1 answer:
Vinil7 [7]3 years ago
8 0
|3-v| < 6

1) Write the inequality as two inequalities without absolute value:
1st inequality:   3 < 6
2nd inequality: -v < 6

2) 
|3-v| < 6
<u>-3       -3</u>
|-v|   < 3
  v < 3

v = 2

3 - v < 6
3 - 2 < 6
1 < 6

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Tcecarenko [31]
25d^2-30d-35d+42=25d^2-65d+42.
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3 years ago
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A natural number _a rational number.
lora16 [44]
A natural number is a positive integer, example, 1,2,5,299 etc.
A rational number is a number that can be expressed as a fraction of integers, such as 245/127, 1/2, 5/1,8/1,...
Since a natural number can be expressed as a fraction of integers, so 

a natural number IS a rational number.
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What are the outputs of the following function?
NISA [10]

Answer:

-2

Step-by-step explanation:

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3 years ago
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Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
3 years ago
A partir del 1.° de diciembre, un camión de helados visita la calle de Sara cada 3 días y la calle de Ema cada 5 días. ¿Cuáles s
777dan777 [17]

Answer:

Los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.

Step-by-step explanation:

Los múltiplos de un número son todos los posibles resultados de multiplicar ese número por todos y cada uno de los números naturales.

Es decir, los múltiplos de un número natural son los números naturales que resultan de multiplicar ese número por otros números naturales.

El conjunto de los múltiplos de un número determinado (salvo el cero) es infinito, pues existen infinitos naturales para multiplicar.

Para determinar cuáles son los primeros 2 días que el camión visita ambas calles el mismo día, debes encontrar los múltiplos de 3 y 5:

múltiplos de 3: 3; 6; 9; 12; 15; 18; 21; 24; 27; 30

múltiplos de 5: 5; 10; 15; 20; 25; 30; 35; 40; 45; 50

Podes observar que los 2 primeros números comunes o que coinciden entre los múltiplos de 3 y 5 son 15 y 30. Esto quiere decir que <u><em>los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.</em></u>

7 0
2 years ago
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