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3 years ago

Why can't you use the product of powers rule to simplify this expression? Explain. 3^4.2^8

Mathematics

1 answer:

Tema [17]3 years ago

3 0

Answer:

Because the base of this expression is not same.

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Describe all situation where vertical angles are also supplementary

Nataly_w [17]

Vertical angles are always the same size. if they are supplementary the measures must add to 180. 180/2=90. vertical angles are supplementary only when they are right angles, our 90°

3 0

3 years ago

Read 2 more answers

I pleased anyone to help me please

Gennadij [26K]

Answer:

The first one (90, 90) is supplimentary, the next two (54, 36. and 45, 45) are complimentary, and the last two are supplimentary.

Step-by-step explanation:

A complimentary angle is two angles that add up to 90, and supplimentary is two angles that add up to 180! :)

3 0

2 years ago

Read 2 more answers

I need some help with this

masya89 [10]

Answer:

A, C, D

Step-by-step explanation:

Consider triangles NKL and NML. These triangles are right triangles, because

$m\angle K=m\angle M=90^{\circ}$

In these right triangles:

$\overline{NL}\cong \overline {NL}$ - reflexive property;
$\angle KLN\cong \angle MLN$ - given

Thus, triangles NKL and NML by HA postulate. Congruent triangles have congruent corresponding parts, so

$\overline{KN}\cong \overline{NM}\\ \\\overline{KL}\cong \overline{LM}\ [\text{option D is true}]$

Since

$\overline{KN}\cong \overline{NM},$

then

$7x-4=5x+12\\ \\7x-5x=12+4\\ \\2x=16\\ \\x=8\ [\text{option A is true}]\\ \\MN=KN=7\cdot 8-4=56-4=52\ [\text{option C is true}]$

Option B is false, because KN=52 units.

Option E is false, because LN is congruent KN, not LM

4 0

2 years ago

Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required

xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

$A = Pe^{rt}$

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

A = 2 × $3000

A = $6000

$6000 = 3000e^{0.085t}$

$\frac{6000}{3000} = e^{0.085t}$

$2 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}2 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln2 = 0.085t$

$t = \frac{ln2}{0.085}$

$t = \frac{0.693}{0.085}$

t = 8.15

(b) For the amount to double, A = 3 × P

A = 3 × $3000

A = $9000

$9000 = 3000e^{0.085t}$

$\frac{9000}{3000} = e^{0.085t}$

$3 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}3 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln3 = 0.085t$

$t = \frac{ln3}{0.085}$

$t = \frac{1.0986}{0.085}$

t = 12.92

5 0

3 years ago

Which statement is true about the solution ?

Harrizon [31]

Answer:

There are no real solutions to this equation

Step-by-step explanation:

4 0

2 years ago