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agasfer [191]
3 years ago
14

Using the graph below, find the point(s) such that the sum of their coordinates is equal to 7.

Mathematics
1 answer:
gregori [183]3 years ago
7 0

Answer:

Only A, B and C are the points whose coordinates are equal to 7.

Step-by-step explanation:

Considering the point A

As the location of point A is (0, 7)

The sum of their coordinates is equal to 0 + 7 = 7

Considering the point B

As the location of point B is (2, 5)

The sum of their coordinates is equal to 2 + 5 = 7

Considering the point C

As the location of point C is (6, 1)

The sum of their coordinates is equal to 6 + 1 = 7

Considering the point D

As the location of point D is (4, -3)

The sum of their coordinates is equal to 4 + ( -3 ) = 1

Considering the point E

As the location of point E is (1, -6)

The sum of their coordinates is equal to 1 + ( -6 ) = -5

Considering the point F

As the location of point F is (-2, -4)

The sum of their coordinates is equal to -2 + ( -4 ) = -2 - 4 = -6

Considering the point G

As the location of point F is (-5, -2)

The sum of their coordinates is equal to -5 + ( -2 ) = -5 - 2 = -7

Considering the point H

As the location of point H is (-4, 3)

The sum of their coordinates is equal to -4 + ( 3 ) = -4 + 3 = -1

From the above discussion, only A, B and C are the points whose coordinates are equal to 7.

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Step-by-step explanation:

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What is one benefit of privately issued student loans?
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Answer:

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(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

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P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

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Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

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