Answer:
a)
b)
Step-by-step explanation:
By definition, we have that the change rate of salt in the tank is , where is the rate of salt entering and is the rate of salt going outside.
Then we have, , and
So we obtain. , then
, and using the integrating factor , therefore , we get , after integrating both sides , therefore , to find we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions , so
Finally we can write an expression for the amount of salt in the tank at any time t, it is
b) The tank will overflow due Rin>Rout, at a rate of , due we have 500 L to overflow , so we can evualuate the expression of a) , is the salt concentration when the tank overflows
Well first you have to know what i is. i is the sqrt of -1 so try doing 3+5(sqrt-1)/1+sqrt-1. I don't know how to solve it though sorry
3y+14=44
Answer: First step is to subtract 14 from each side
3y = 30 (divide each side by 3)
y = 30/3, y = 10
Answer:
x=(k√x)/(w^2)(cube√z)
x varies directly with square root of y is:
x = k √y
And inversely with the square of w and cube root of s is:
/(w^2)(cube√z)
Now put those together:
x=(k√x)/(w^2)(cube√z)
The formula is:
x=ky/wz but add the specific info like square, roots, or etc