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kupik [55]
3 years ago
15

Point X is at 2/3 on a number line. On the same number line, point Y is the sane distance for 0 as point X, but has a numerator

of 8. What is the Denominator of the fraction on point Y?
Mathematics
1 answer:
olga2289 [7]3 years ago
4 0

Answer:

12

Step-by-step explanation:

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two years ago a woman was 7 times old as her daughter, but in 3 years time she would be 4 times old as the girl. how old are the
bonufazy [111]

Let present age of women be x.

Then,Present age of her daughter be y.

According to the question,

<u>Two years ago,</u>

Woman age = x - 2

Her daughter age = y - 2

Woman was 7 times old as her daughter. [ Given ]

x - 2 = 7 ( y - 2 )

=> x - 2 = 7y - 14

=> x - 2 + 14 = 7y

=> x + 12 = 7y ....( i )

<u>A</u><u>f</u><u>t</u><u>e</u><u>r</u><u> </u><u>Three years </u>,

Woman age = x + 3

Her daughter age = y + 3

she would be 4 times old as the girl. [ Given ]

x + 3 = 4 ( y + 3 )

=> x + 3 = 4y + 12

=> x = 4y + 12 - 3

=> x = 4y + 9....( ii (

Now,

★ Putting the value of x = 4y + 9 from equation ( ii ) in equation ( i ),we get

x + 12 = 7y

=> 4y + 9 + 12 = 7y

=> 21 = 7y - 4y

=> 21 = 3y

=> 3y = 21

=> y = 21/3

=> y = 7

And,

x = 4y + 9

★ Putting the value of y in equation ( ii ), we get

x = 4 × 7 + 9

x = 28 + 9

x = 37

Hence, the present age of women is 37 years and her daughter age is 7.

8 0
3 years ago
The cylinders are similar. The volume of the larger cylinder is 9648 cubic inches. What is the volume of the smaller cylinder?
zalisa [80]
Hey there :)

The volume formula of a cylinder is:
V = \pir²h

The volume of the larger volume is given to be 9648³ and the height is 18 in
We need to find the radius first

9648 = \pir²(18)
\frac{9648}{18} = \pir²
536 = \pir²
\frac{536}{ \pi} = r²
\sqrt{ \frac{536}{ \pi } } = r
r ≈ 13.06

The ratio of the big cylinder to small cylinder is:
18 : 9   (given height)
So the big cylinder is 2 times bigger than the small cylinder
Therefore the radius of the big cylinder is as well 2 times bigger

\frac{13.06}{2} = r
r ≈ 6.53  ( the radius of the small radius )

V (of small cylinder) = \pi(6.53)²(9)
                                  = 1206 in³
3 0
3 years ago
Refer to the accompanying data set of mean​ drive-through service times at dinner in seconds at two fast food restaurants. const
Anton [14]

Step-by-step explanation:

Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.

The standard error is SE = s/√n = 62.6/√50 = 8.85.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

180.56 ± 1.960 × 8.85

180.56 ± 17.35

(163, 198)

Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.

The standard error is SE = s/√n = 49.2/√50 = 6.96.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

152.96 ± 1.960 × 6.96

152.96 ± 13.64

(139, 167)

4 0
3 years ago
To celebrate there 125 anniversary, a company in Germany produced 125 very expensive teddy bears. The bears,known as the "125 ka
liq [111]

Answer:

The cost of one bear is <u>$47,000</u>.

Step-by-step explanation:

The question is incomplete and the data is missing so the complete question with data is below with attached files:

To celebrate there 125 anniversary, a company in Germany produced 125 very expensive teddy bears. The bears,known as the "125 karat teddy bears", are made mohair,silk and gold thread and have diamond and sapphire eyes.

The chart shows the approximate cost of " 125 teddy bears". Based on the pattern, how much does one bear cost?

Now, to get the cost of one bear.

So, we solve it by using unitary method:

If 4 bears cost = $188,000.

Then 1 bear cost = 188000\div 4=47000

Thus, cost of one bear is $47,000.

Now, we check it by using another pattern of the data:

If 7 bears cost = $329,000.

Then 1 bear cost = 329000\div 7=47000.

Hence, the cost of one bear is $47,000.

Therefore, the cost of one bear is $47,000.

8 0
3 years ago
A particular fruit's weights are normally distributed, with a mean of 406 grams and a standard deviation of 27 grams.The heavies
Tom [10]

Given

mean of 406 grams and a standard deviation of 27 grams.

Find

The heaviest 14% of fruits weigh more than how many grams?

Explanation

given

mean = 406 gms

standard deviation = 27 gms

using standard normal table ,

\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}

Final Answer

Therefore , The heaviest 14% of fruits weigh more than 435.16 gms

8 0
1 year ago
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