All categories

4 years ago

|-2x + 4| > or equal to 4

1 answer:

7 0

$\text{When you solve for absolute value, there could be two possible outcomes}\\\\\text{In this question, the outcomes could be:}\\\\-2x+4\geq4\\\text{or}\\\\-2x+4\geq-4\\\\\text{Solve:}\\\\\text{Possibility 1:}\\\\-2x+4\geq4\\\\\text{Subtract 4 from both sides}\\\\-2x\geq0\\\\\boxed{x\leq0}\\\\\text{Possibility 2:}\\\\-2x+4\geq-4\\\\-2x\geq-8\\\\\boxed{x\geq4}$

You might be interested in

Please help! Will mark brainliest!

Oksi-84 [34.3K]

Sorry, misunderstood question, answer beneath me much better.

8 0

3 years ago

Read 2 more answers

Please please please please help me someone

Shtirlitz [24]

Answer:

That incorrect

Step-by-step explanation:

Yes

3 0

3 years ago

A radar is designed to report the track of an aircraft every 2 seconds. If this radar reports 15 reports 15 tracks in one minute

meriva

Answer:

Step-by-step explanation:

Since radar reports 30 tracks in one minute in which 60 seconds makes 1 minute

Let calculate using this formula

Using this formula

Percentage of time=Tracks reported in minutes/60 seconds*100

Let plug in the formula

Percentage of time=30 tracks/60 seconds*100

Percentage of time=0.5*100

Percentage of time=50%

Inconclusion The percentage of the time that radar track the aircraft is 50%

5 0

3 years ago

Read 2 more answers

Prove divisibility 45^45·15^15 by 75^30

Anuta_ua [19.1K]

Answer:

$3^{75}$

Step-by-step explanation:

We are asked to divide our given fraction: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(3*15)^{45}=3^{45}*15^{45}$

$75^{30}=(5*15)^{30}=5^{30}*15^{30}$

Substituting these values in our division problem we will get,

$\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}$

$\frac{3^{45}*15^{60}}{5^{30}*15^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{45}*15^{60-30}}{5^{30}}$

$\frac{3^{45}*15^{30}}{5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{3^{45}*(3*5)^{30}}{5^{30}}$

$\frac{3^{45}*3^{30}*5^{30}}{5^{30}}$

Upon canceling out $5^{30}$ we will get,

$3^{45}*3^{30}$

Using power rule of exponents $a^m*a^n=a^{m+n}$ we will get,

$3^{45+30}$

$3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

8 0

3 years ago

PLEASE HELP WITH THIS! <br> if there's is work PLEASE include thank you:) I need # 27 btw

amid [387]

Order.

9, 12, 12, 14, 15, 16, 18, 21

Now split into quarters.

9, 12, 12, 14, 15, 16, 18, 21
| | |
(1) (3)

Determine the values of (1) and (3) by using medians.

14 + 12 + 12 + 9 / 4
47 / 4
approx. 12

So Q1 = 12.

15 + 16 + 18 + 21 / 4
70 / 4
approx. 17

Therefore the answer is C I think. I have not done this ever before. All the knowledge I did was from research lol

8 0

3 years ago