Suppose f(x)=x^3 find the graph of f(x+1)
1 answer:
You might be interested in
The spinner is divided into four equal sections: 2, 4, 7, 9. This represents 4 possibilities
If the spinner is spun twice, the sample space is:
For product less than 30, the number of outcomes is shown below:
The number of outcomes that have a product less than 30 = 10
The sample space that shows possibilities of an odd number combination:
The number of outcomes that contains at least one odd number = 12
The number of outcomes that have a product less than 30 and contain at least one odd number is shown below. These outcomes are outcomes circled in both cases shown above,
The outcomes circled represents the number of outcomes that has a product less than 30 and contains at least one odd number
Answer: 6 (option B)
