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emmainna [20.7K]
4 years ago
8

Which of the following has the least value?

Mathematics
2 answers:
yawa3891 [41]4 years ago
5 0
C hope this helps follow me for a follow
Sonja [21]4 years ago
3 0
It most likely going to be A.
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You have 1200 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in
NARA [144]

Let x = length and y = width

You would have 2 lengths, so 2x and 3 widths, so 3y

Those need to equal total length of fence:

2x + 3y = 1200

The 3 widths would equal total fence minus the 2 lengths:

3Y = 1200-2x

Solve for y: y = 400 -2/3x

Area = length x width = xy. Replace y :

Area = x(400-2/3x) = 400x-2/3x^2

Differentiate:

400-4x/3 =0

4x/3 = 400

4x = 1200

X = 300

Y = 400-2/3(300) = 200

The dimension would be 300 ft x 200 ft

7 0
3 years ago
Simplify the expression using properties of exponents.<br><br> 12a-9b-4<br><br> 9a2b6
Free_Kalibri [48]
Check out -m-a-t-h-w-a-y-.-c-o-m- (This helps a lot!)
5 0
3 years ago
Find four geometric means between 25 and 800.
SVEN [57.7K]

Actually, you have to find four missed terms of geometrical sequence. Denote

a_1=25,\\ a_6=800

and r - ratio, then

a_2=a_1\cdot r=25r,\\a_3=a_1\cdot r^2=25r^2,\\a_4=a_1\cdot r^3=25r^3,\\a_5=a_1\cdot r^4=25r^4,\\a_6=a_1\cdot r^5=25r^5.

Since a_6=800, you have that 800=25r^5, then

r^5=\dfrac{800}{25} =32,\\r=2.

Now substitude r=2 in each of unknown 4 terms:

a_2=25\cdot 2=50,\\a_3=25\cdot 2^2=100,\\a_4=25\cdot 2^3=200,\\a_5=25\cdot 2^4=400.

Answer: four geometric means between 25 and 800 are 50, 100, 200, 400.

8 0
4 years ago
Pls help asap I’ll give brainliest!!!!!!!!
bonufazy [111]

Step-by-step explanation:

Find the MEAN with the information you have. Then say th edifference between the mean on the graph and the median.

8 0
2 years ago
Frank wrote 1/4 of his book
Ede4ka [16]
Let’s make common denominator
1/4 * 2/2 = 2/8 before dinner
1/8 after dinner
2/8 + 1/8 = 3/8
He finished 3/8 of the report
7 0
2 years ago
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