Answer: Cam did not use a zero place holder for the x^3 term
Step-by-step explanation:
Answer:
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Its simple, convert 1 and 2/3 into a fraction which is 5/3 and use KCF which is Keep Change and Flip,
How this works is that you keep the first fraction, then change the division sign to a multiplication sign (Change = change the sign into its oppisite) then flip the other fraction from being 5/3 into 3/5. And then you multiply top times top and bottom times bottom. After that you simplify if you can, Hope this helped!
Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
Learn more : brainly.com/question/18405415
