we are given with two dice and that we are asked in the problem to find the probability of the following:
a. sum at least 4b. sum at least 6
THe sample space of this problem is
{11, 12, 13, 14, 15, 16, 21,22, 23,24,25,26,31,32,33,34,35,36,41,42,43,44,45,46,51,52,53,54,55,56,61,62,63,64,65,66} a total of 36.a. 33/36 = 11/12b.11/36
Nice you do not know the price of the child's ticket, you represent it as X. Then you add the 2.75 to the variable. You take the unknown number and add the known. so the answer would be x+2.75
Answer:
$659.25
Step-by-step explanation:
Since its 25 percent off we need to see what it would look as a decimal
1-.25=.75
879times.75= 659.25
You would use pythagoras theorem which would be
16m