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lorasvet [3.4K]
3 years ago
11

Find the volume.!!!!

Mathematics
2 answers:
vampirchik [111]3 years ago
8 0

Answer:

well the answer is multiplying all of the numbers

3.5 times 5 times 4 is 70

Step-by-step explanation:

The answer is 70

ankoles [38]3 years ago
3 0
V=70cm^3

multiply length/width/height to get the volume
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If x10=235 find x <br> Answer needed ASAP please
nikdorinn [45]

Answer:

23.5 is the answer

Step-by-step explanation:

X10 =235 so x=235÷10 = 23.5

5 0
2 years ago
Read 2 more answers
What is the value of y?
Molodets [167]
B, because
3/15=x/75
75/15=5
3*5=15
15 is your answer.
4 0
3 years ago
30 students in a class took an algebra test.
lesya [120]

Answer:

70%

Step-by-step explanation:

21/30      p/100

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2 years ago
After Halloween, a variety store had some costumes regularly priced at $20.50 on sale for 20% off the regular price. A few weeks
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20.50 * 0.8 = $16.40

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6 0
3 years ago
To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo
mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}

Given:

\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25

Confidence level = 80%

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0
2 years ago
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