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2 years ago

Write 4 3/5 as an improper fraction.

Mathematics

2 answers:

Andrews [41]2 years ago

8 0

Answer:

$\frac{23}{5}$

Step-by-step explanation:

4 3/5

$\frac{4 \times 5 + 3}{5}$

$\frac{20 + 3}{5}$

= 23/5

Ugo [173]2 years ago

8 0

Answer:

23/5 hope this helps you bro please mark brainliest

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Please help!! | show work and do not guess. :)

Olegator [25]

The answer would be b A≈1636.8

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3 years ago

Sahir took 1 h 22 min to do his english homework 45 min to do his maths homework, and 10 min to do his urdu. How long did he tak

andre [41]

Answer:

2 hr and 17 minutes

Step-by-step explanation:

add 45 to 10+= 55

55+ 1 hr 22 = 1 hour and 77 minutes which converts to:

2 hour and 17 minutes

good luck!

6 0

2 years ago

If EG = 3y - 10 and ET = 2y, find the value of y In parallelogram FGHI.<br> 1<br> Find Value of y.

Ksenya-84 [330]

<h3>Answer: y = 10</h3>

=====================================

Work Shown:

EI = EG

3y-10 = 2y

3y-10-2y = 0

y-10 = 0

y = 0+10

y = 10

Note how if y = 10, then

EI = 3y-10 = 3*10-10 = 20
EG = 2y = 2*10 = 20

Both EI and EG are 20 units long when y = 10. This confirms the answer.

6 0

2 years ago

PLEASE HELP Which of the following is false about the Y intercept

Flauer [41]

The answer choice that is false is D.

The form of the y-intercept is (0,Y). Remember that x comes first in an ordered pair and y comes second.

Hope this helps!

7 0

2 years ago

Oh no! Thomas is lost in the GGBL building after an exam, and trying to get out. Thereare four identical hallways leading away f

Brums [2.3K]

Answer:

Check the explanation

Step-by-step explanation:

Since each and every one of the 4 hallways is equally likely then

$P(H1)=1/4P(H2)=1/2P(H3)=1/4$

Now, if he chooses H1 he escapes after 12 minutes then

$E(T|H1)=12$

If he chooses H2 then he wastes 10 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

$E(T|H2)=10+E(T)$

Analogously, if he chooses H3 then he wastes 40 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

$E(T|H3)=40+E(T)$

Therefore

$E(T) = E(T|H1)P(H1) + E(T|H2)P(H2) + E(T H3)P(H3) = (12) + (E(T) +10) + (E(T) + 40) = 3+ *E(T)+5+ 10 = E(T) +18 CON A'$

So we have

$E(T) = E(T) + 18 E(T) = 18 E(T) = 4(18) = 72$

Therefore he is expected to escape in 72 minutes

7 0

3 years ago