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kobusy [5.1K]
4 years ago
5

Between points 1 and 2, water is a _____. a. gas b. solid c. plasma d. liquid

Chemistry
1 answer:
zloy xaker [14]4 years ago
7 0
Your answer would be 
d. liquid

:)
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Introduced sewage in water systems _______. a. decreases levels of phosphorus and nitrogen b. increases oxygen levels c. increas
enyata [817]

Option C: Introducing sewage in water systems increases the concentration of solids.

Sewage is one of the most concerning sources of water pollution. Sewage, in simple terms, is the wastewater that contains compostable materials from the kitchen, industries, bathrooms, etc.

When untreated sewage is introduced into the water bodies, the microorganisms in it take up the oxygen from water for their aerobic respiration. As a result, the resident organisms of the water body have to struggle to survive due to the lack of oxygen in the water.

Sewage also contributes to the eutrophication of water bodies. Eutrophication is the process by which the nutritional elements, like phosphates and nitrates, in a water body, are enhanced causing the microorganisms to feast over them.

Sewage has some solid particles that can't be dissolved or decomposed. This then leads to the concentration of solids at the base of the water body. This further leads to the growth of various organisms using dissolved oxygen and leads to the deterioration of water quality.

To know more about sewage water, refer to the following link:

brainly.com/question/10022625

#SPJ4

8 0
2 years ago
Ionic compounds are formed from ionic bonds, whereby an electron is transferred from the metal cation to the nonmetal anion. Ion
Karolina [17]

Answer:

NaI

Explanation:

In I₂, HI and IBr, both atoms are nonmetals and they form covalent bonds in which electrons are shared.

In NaI, Na is a metal and I a nonmetal, so they form an ionic bond, where Na loses an electron to form Na⁺ and I gains an electron to form I⁻.  Anions and cations are attracted to each other through electrostatic forces.

Since ionic bonds are stronger than covalent bonds, more energy is required to break them in the melting process, thus having higher melting points.

All in all, NaI is the one with the highest melting point.

7 0
4 years ago
5. A gas has a pressure of 310 kPa at 237 degrees C.<br>What will its pressure be at 23 degrees C?)​
slavikrds [6]

Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Studying two states, one initial 1 and the other final 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 310 kPa
  • T1= 237 C= 510 K (being 0 C= 273 K)
  • P2= ?
  • T2= 23 C= 296 K

Replacing:

\frac{310 kPa}{510 K} =\frac{P2}{296 K}

Solving:

P2=296 K*\frac{310 kPa}{510 K}

P2= 179.92 kPa

<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>

5 0
3 years ago
What is the concentration of a solution of HBr if 0.40 L is neutralized by 0.20 L of 0.50M solution of LiOH?
marysya [2.9K]
Since the mole ratio is 1 to 1 for this reaction, you can just use M1V1 = M2V2 to solve, given that 1 refers to HBr and 2 refers to LiOH.

M1 = ?
V1 = 0.40 L
M2 = 0.50 M
V2 = 0.20 L

M1(0.40) = (0.50)(0.20)

Solve for M1 —> M1 = (0.50)(0.20)/0.40 = 0.25 M HBr
4 0
3 years ago
If 588 grams of FeS2 is allowed to react with 352 grams of O2 according to the following equation, how many grams of Fe2O3 are p
Rainbow [258]

<u>Answer:</u> The mass of iron (III) oxide  produced is 782.5 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For </u>FeS_2<u> :</u>

Given mass of FeS_2 = 588 g

Molar mass of FeS_2 = 120 g/mol

Putting values in equation 1, we get:

\text{Moles of }FeS_2=\frac{588g}{120g/mol}=4.9mol

  • <u>For </u>O_2<u> :</u>

Given mass of O_2 = 352 g

Molar mass of O_2 = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of }O_2=\frac{352g}{32g/mol}=11mol

The chemical equation for the reaction of FeS_2 and oxygen gas follows:

FeS_2+O_2\rightarrow Fe_2O_3+SO_2

By Stoichiometry of the reaction:

1 mole of FeS_2 reacts with 1 mole of oxygen gas

So, 4.9 moles of FeS_2 will react with = \frac{1}{1}\times 4.9=4.9mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, FeS_2 is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of FeS_2 produces 1 mole of iron (III) oxide

So, 4.9 moles of FeS_2 will produce = \frac{1}{1}\times 4.9=4.9moles of iron (III) oxide

Now, calculating the mass of iron (III) oxide  from equation 1, we get:

Molar mass of iron (III) oxide  = 159.7 g/mol

Moles of iron (III) oxide  = 4.9 moles

Putting values in equation 1, we get:

4.9mol=\frac{\text{Mass of iron (III) oxide}}{159.7g/mol}\\\\\text{Mass of iron (III) oxide}=(4.9mol\times 159.7g/mol)=782.5g

Hence, the mass of iron (III) oxide  produced is 782.5 grams

8 0
3 years ago
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