Question

A company makes a cone-shaped container with a height of 15 in. The area of its base is about 78.8in.2 Approximately what is the volume of the container?

Answer 1

Answer:

Approximately the volume of cone-shaped container is 393 in³.

Step-by-step explanation:

Given:

A company makes a cone-shaped container with a height of 15 in.

The area of its base is about 78.8 in².

Now, to get the cone-shaped container volume.

So, we find the radius first by using formula:

Let the radius be $r.$

(Using the value π = 3.14)

$A_{B}=78.8\ in^2.$

$A_{B}=\pi r^2$

$78.8=3.14\times r^2$

Dividing both sides by 3.14 we get:

$25.09=r^2$

Using square root on both sides we get:

$5.00=r$

$r=5\ in.$

Thus, the radius ($r$) = 5 in.

The height ($h$) = 15 in.

Now, to get the volume of the cone-shaped container we put formula:

$Volume=\pi r^2\frac{h}{3}$

$Volume=3.14\times 5^2\times \frac{15}{3} \\\\Volume=3.14\times 25\times 5\\\\Volume=392.50\ in^3.$

Therefore, approximately the volume of the cone-shaped container is 393 in³.