The answer will be start fraction pi over 2 end fraction
Answer:
Step-by-step explanation:
Joint variations occurs when one variable depends on the value of two or more variables. The variable varies directly or indirectly with the other variables combined together. The other variables are held constant. From the given examples, the equation(s) that represent joint variations are
1) z = 3x/y
z varies directly with x and inversely with y.
2) w = abc/4
w varies inversely with a,b and c. 4 is the value of the constant of variation.
Answer:
imagine
Step-by-step explanation:
Answer:
independent: miles
dependent: minutes/hours
Step-by-step explanation:
can I see the other options for the rest?
Answer:

Step-by-step explanation:
<u>Area of a Compound Shape</u>
The shape shown in the image is made of two shapes: Half a circle of radius 8 m and a triangle of base 24 m and height 16 m.
The area of a circle of radius r is:

The area of a triangle of base b and height h is:

Calculate the area of the circle:


Area of half the circle:

Area of the triangle:


The area of the shaded shape is:

Substituting the value of pi:
