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lina2011 [118]
3 years ago
10

What is the value of the digit in the ten thousands place in 1,631,192

Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:30,000

Step-by-step explanation:

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Which graph represents the piecewise-defined function?
Valentin [98]

Answer: The below figure shows the graph of f(x).

Explanation: Given function, f(x)=\begin{cases}5 & \text{ if } x6 \end{cases}

Since, here three conditions are given,

In first case for values x<-5 , f(x)=5, so we get a line y=5 parallel to x-axis which passes through point (0,5).

In second case, for values  -5\leq x\leq 6, f(x) =-2, so we get a line y=-2 parallel to x-axis which passes through point  (0,-2).

In third case, for values x>6, f(x)=1, so we get a line y=1 parallel to x-axis which passes through point (0,1).

Thus, these three lines make the piecewise-defined function f(x).

7 0
3 years ago
Read 2 more answers
A cable is <br> 40<br><br> meters long. How long is the cable in decimeters?
AnnyKZ [126]
Hello,

1 meter is equal to 10 decimeters.

SO, 
if we convert 40 meters to decimeters, we multiply 40 meters by 10 decimeters, getting 400 decimeters.

Hope this helps!

May
6 0
3 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
3 years ago
On a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice hi
Lina20 [59]

Answer:

Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.

Step-by-step explanation:

Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.

Given that he spent 5 hours in driving.

And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.

Given that his average rate in the morning was twice his average rate in the afternoon.

(150/x) = 2 * 50/(5-x)

150/x = 100/(5-x)

Cross multiplying terms, we get:-

150*(5-x) = 100*x

750 - 150x = 100x

750 = 100x + 150x

750 = 250x

x = 750/250 = 3.

It means he spent 3 hours in the morning and 2 hours in the afternoon.

So morning's average rate = 150/3 = 50 mph.

and afternoon's average rate = 50/(5-3) = 25 mph.

8 0
3 years ago
2y)(2y + 8) = ? A. 4xy – 16x – 4y2 – 16y B. 4xy + 16x – 4y2 – 16y C. 4xy – 4y2 D. 4xy + 16x + 4y2 + 16y 8…
Vilka [71]
4y^2 + 16y
You distribute the 2y into the 2y+8
8 0
3 years ago
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