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Andre45 [30]
2 years ago
13

The weights of the fish in a certain lake are normally distributed with a mean of 20 lb and a standard deviation of 9. If 9 fish

are randomly selected, what is the probability that the mean weight will be between 17.6 and 23.6 lb
Mathematics
1 answer:
mr Goodwill [35]2 years ago
3 0

Step-by-step explanation:

mean of 20 lb and a standard deviation of 9. If 9 fish are randomly selected,

what is the probability that the mean weight will be between 17.6 and 23.6

Ib? Write your answer as a decimal rounded to 4 places

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The orange one is the answer

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3 years ago
How do you solve 58 and 1/3÷6 and 2/3
strojnjashka [21]

Answer:

35/4, or 8 3/4 as a mixed number

Step-by-step explanation:

First, change 58 1/3 into an improper fraction by multiplying the whole number and denominator, then adding the numerator. 58 x 3 equals 174, + 1 equals 175. So, 58 1/3 as an improper fraction is 175/3. Next, change 6 2/3 into an improper fraction. 6 times 3 equals 18, plus 2 equals 20. So, it's 20/3. So, here are your two fractions:

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Rudiy27

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