Explanation:
In order to prove that affirmation, we define the function g over the interval [0, 1/2] with the formula 
If we evaluate g at the endpoints we have
g(0) = f(1/2)-f(0) = f(1/2) - f(1) (because f(0) = f(1))
g(1/2) = f(1) - f(1/2) = -g(0)
Since g(1/2) = -g(0), we have one chance out of three
- g(0) > 0 and g(1/2) < 0
- g(0) < 0 and g(1/2) > 0
- g(0) = g(1/2) = 0
We will prove that g has a zero on [0,1/2]. If g(0) = 0, then it is trivial. If g(0) ≠ 0, then we are in one of the first two cases, and therefore g(0) * g(1/2) < 0. Since f is continuous, so is g. Bolzano's Theorem assures that there exists c in (0,1/2) such that g(c) = 0. This proves that g has at least one zero on [0,1/2].
Let c be a 0 of g, then we have
Hence, f(c+1/2) = f(c) as we wanted.
Answer:
10
Step-by-step explanation:
*I’m assuming that you meant y = 2x^2-3 because that is what my RSM problem was and it was exactly the same problem other than that.* First you want to find the points of intersection of the two parabolas. You can choose to graph them or do any other method. Anyways, the points of intersection are: (2,5) and (-2,5). You now want to add (0,0). So obviously (2,5) to (-2,5) is the base and it is 4 units. The height is 0 to 5 which is 5 units. Do (4*5)/2 and you get 10. Hope this helped you with your RSM and let me know if I assumed correctly.
It would be 3 because tidncirnsis fiznawlslzlmrfi
Answer:
18 weeks
Step-by-step explanation:
Initial amount stored in savings account = $700
Final minimum amount required in the account = $150.
Thus,
The total amount of money he can spend = (700 - 150) = $550
Each week he is withdrawing $30 to go out to eat.
Since , maximum money he can spend should be multiple of 30 ,
Thus maximum he can spend $540
number of weeks he can do this = 
= 18.
So, he can take out $30 each week to go out to eat for 18 weeks only.
Answer:
3 cm and 1.75 cm
Step-by-step explanation:
the numbers have to coincide with the ones being compared in the same amount. like 3×2=6 and its the same with 1.75×2=3.50
