All categories

3 years ago

Find the circumference and area of a circle with a diameter of 22 inches. Leave your answers in terms of pi.

1 answer:

4 0

The answer for this will be letter d. C = 22π and A = 121π. This is computed using the formula of C= Dπ which is C = (22)π. On the other hand, the area of this circle is computed by using the formula A = πr^2. This is computed as follows:
A = πr^2
A = π (22/2)^2
A = π (11)^2
A = 121π

You might be interested in

In the state of Pennsylvania 12% of students submit box tops for education to their school. A large school district in western P

Eddi Din [679]

Add more information

3 0

3 years ago

Let the function be f defined by f (x) = 12 - 5x

marissa [1.9K]

(a) No

$f(x) = 12 - 5x$

$f(0) = 12 - 5(0)$

$f(x) = 12 - 0$

$f(x) = 12$

Hence,

f(0) is unequal to 0.

(b)

$f(x) = 12 - 5x$

$f( - 1) = 12 - 5( - 1)$

$f( - 1) = 12 + 5$

$f( - 1) = 17$

(c)

$f(x) = 12 - 5x$

$f(x) = 6$

$6 = 12 - 5x$

$6 - 12 = - 5x$

$- 6 = - 5x$

$6 = 5x$

$\frac{6}{5} = x$

7 0

3 years ago

using a special discount you download 15 songs for $10.86 the regular price of each song is $0.89. What is the percent of the di

gayaneshka [121]

Answer:

23%

Step-by-step explanation:

4 0

2 years ago

What are the answers for these graphs?

Masteriza [31]

Answer:

MArk me brainliest plz i need it

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Use CALCULUS to find coordinates of the turning point on C.

antiseptic1488 [7]

Oi

Just calculating the differential. Step by step:

$y=12 \sqrt{x} -x \frac{3}{2}-10 \\ \\ y=12x^{ \frac{1}{2} } -x \frac{3}{2}-10 \ \ \ \boxed{transform \ \sqrt{x} =x^{ \frac{1}{2} }} \\ \\ Differentiating \\ \\ y'=12. \frac{1}{2}.x^{ \frac{1}{2}-1 } -1.x^{1-1}. \frac{3}{2}-0 \\ \\ y'=6.x^{ -\frac{1}{2} } -x^{0}. \frac{3}{2} \\ \\ y'=6. \frac{1}{x^{ \frac{1}{2} }} -1. \frac{3}{2} \\ \\ \boxed{y'=\frac{6}{ \sqrt{x} } -\frac{3}{2}}$

If you want to know where the tangent has no slope:

$\frac{6}{ \sqrt{x} } - \frac{3}{2} =0 \\ \\ \frac{6}{ \sqrt{x} } = \frac{3}{2} \\ \\ 3 \sqrt{x} =12 \\ \\ \sqrt{x} = \frac{12}{3} \\ \\ \sqrt{x} =4 \\ \\ (\sqrt{x})^2 =4^2 \\ \\ x=16$

3 0

3 years ago