Answer:
Positive y-axis
Explanation:
First of all, we need to find the direction of the magnetic force.
We know that the direction of the magnetic force on a charged moving particles is perpendicular to both the velocity of the particle and the direction of the magnetic field. For a positive charged particle, we can use the right-hand rule. In this case, we find:
- index finger: direction of the velocity of the particle (positive x-axis)
- middle finger: direction of the magnetic field (positive z-axis)
- thumb: direction of the magnetic force (in this case, negative y-axis)
Therefore, the direction of the magnetic force is in the negative y-axis.
In order for the particle to not change its velocity (so, being undeflected), the electric force must balance the magnetic force: therefore, the electric force must be in the opposite direction as the magnetic force, so in the
positive y-axis
direction.
We also know that for a positively charged particle ,the direction of the electric force is the same as the electric field: therefore, the direction of the electric field is also along the positive y-axis.
I think it would be near the sun due.to high rays of sun
Answer:
Magnification = 1
Explanation:
given data
radius of curvature r = - 0.983 m
image distance u = - 0.155
solution
we get here first focal length that is
Focal length, f = R/2 ...................1
f = -0.4915 m
we use here formula that is
.................2
put here value and we get
<h3>v = 0.155 m </h3>
so
Magnification will be here as
m =
m =
<h3>m = 1</h3>