distance traveled by a uniformly accelerated bike is given as

here we know that



now we will have from above equation


so it will cover the total distance of 300 m
E=mgh. 196=5kg*9.81m/s^2*h. So h=196/(5*9.81)=4m
121 is the answer to your question
C because you don’t put a force of which you choose and the force wouldn’t be strong enough
Answer: 
Explanation:
Given
Length of the race track 
the radius of curvature of the track 
time taken to run on track is 
Speed of runner is

Centripetal acceleration is
