1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elena L [17]
2 years ago
6

Q3. A student plans a method to prepare pure crystals of copper sulfate.

Mathematics
1 answer:
andreev551 [17]2 years ago
3 0

Answer:

1) The student didn't add copper sulfate but instead he added calcium carbonate.

2) The heated solution should be left to get bigger crystals and should not be instantly allowed to evaporate.

3) He should use copper carbonate not calcium carbonate.

4) Sulfuric acid was added instead of hydrochloric acid.

5) Add solid excessively so that all of the acid is retained.

6) Filter the solution to remove unreacted solid.

7) Heat gently, so the crystals will start to appear.

You might be interested in
John looked at his bank account and noticed that he had $2,029.90 in his account. All that he could remember is that he created
Over [174]

We will have that for the previous year, he had in the account:

m_{y6}=2029.90-\frac{2029.90\cdot6}{100}\Rightarrow m_{y6}=1908.106

For the year previous to that one, he had:

m_{y5}=1908.106-\frac{1908.106\cdot6}{100}\Rightarrow m_{y5}=1793.61964

For the previous year to that, he had:

m_{y4}=1793.61964-\frac{1793.61964\cdot6}{100}\Rightarrow m_{y4}=1686.002462

For the year previous to that one, he had:

m_{y3}=1686.002462-\frac{1686.002462\cdot6}{100}\Rightarrow m_{y3}=1584.842314

For the second year that the money was in the account, there was:

m_{y2}=1584.842314-\frac{1584.842314\cdot6}{100}\Rightarrow m_{y2}=1489.751775

And the orinial ammount of money that was in the account was:

m_{y1}=1489.751775-\frac{1489.751775\cdot6}{100}\Rightarrow m_{y1}=1400.366669

From this, we know that Jhon had originally $1400.37 in the bank account.

6 0
8 months ago
Use three fours to make 11.
mr Goodwill [35]
4 + 4 + 4 - 1 = 11? Was it supposed to be an equation? I am confused.
7 0
3 years ago
All rectangles are paralloelograms
Anni [7]

Answer:

not all rectangles are paralloelograms.

Step-by-step explanation:

8 0
2 years ago
Please help me with my homework my homework question
Paladinen [302]

Answer:

(B) Subtract 3x from both sides of the equation, and then divide both sides by 2.

Can't read the second question fully.

(A) 0.53

Step-by-step explanation:

Number 1:

If we have the equation 3x + 2 = 5x, our first goal is to get rid of the x term on one side.

To do this we can subtract 3x from both sides. This leaves our equation to 2=2x. To find x, we want to divide both sides by 2 since 2x divided by 2 is just x. Our goal is to isolate x.  This leaves x=1.

<em>I couldn't read Number 2 fully - I'm sorry :c</em>

<em></em>

Number 3:

Given the equation 3(x+0.2)=2.2, we want to isolate x on one side.

To do this, we first apply the distributive property to the left side.

3x + 0.6 = 2.2

Now subtract 0.6 from both sides:

3x=1.6

And divide both sides by 3.

x=0.5\overline{3}

This rounds to 0.53.

Hope this helped!

7 0
3 years ago
Read 2 more answers
Question 4
g100num [7]
A, 3x5=15 and 3x8=24
4 0
2 years ago
Read 2 more answers
Other questions:
  • Write Numbera In Standard Form
    11·2 answers
  • A train stops 7 times per hour. At this rate, how many stops will it make in 12 hours?
    9·2 answers
  • ^^^<br> Quickly answer please
    8·2 answers
  • HELME PLEASE I WILL MARK THE BRAINEST
    7·1 answer
  • Parker marks sixths on a number line. He writes
    6·1 answer
  • Use similar triangles to calculate the height of triangle abc 10 cm
    11·1 answer
  • Help please it’s needed
    13·1 answer
  • G(x)=2x -3<br> What is the value of<br> G(2) - g(3)
    9·1 answer
  • A postulate is a conjecture that has been proved to be true.
    12·1 answer
  • 3.42x5.15 Please awnswer
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!