All categories

4 years ago

I need help finding a measure

Mathematics

1 answer:

Sedbober [7]4 years ago

8 0

Answer:

Which measure?

Step-by-step explanation:

You might be interested in

Rewrite each sum as a product of the Gcf of the addends and another number. 15+45

morpeh [17]

15 + 45

GCF = 15

15/15 = 1
45/15 = 3

(15 * 1) + (15 * 3) =
15(1 + 3) <===

8 0

4 years ago

1.6.4 the leaky faucet

sveta [45]

Answer:

wot

Step-by-step explanation:

6 0

3 years ago

Think of a number. Double the number. Substract 6 from the result and divide the answer by 2. The quotien will be 20. What is th

cupoosta [38]

Answer:

23 is your answer hope this helps

8 0

3 years ago

Read 2 more answers

In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. But what about on the Moon? If an as

Alex Ar [27]

Answer:

The acceleration due to gravity on the moon is 1.642 m/s².

Step-by-step explanation:

Given : In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. If an astronaut on the surface of the moon swings a 1-meter long pendulum, and it has a period of 4.9 seconds.

To find : What is the acceleration due to gravity, g, on the moon?

Solution :

The pendulum formula is $T=2\pi \sqrt{\frac{L}{g}}$

where, T is the time period,

L is the length of the pendulum,

g is the acceleration due to gravity

We have to find the value of g acceleration due to gravity on the moon.

The formula became,

$g'=(\frac{2\pi}{T})^2\times L$

Substitute T=4.9 seconds , L= 1 m

$g'=(\frac{2\times 3.14}{4.9})^2\times 1$

$g'=(\frac{6.28}{4.9})^2$

$g'=\frac{39.4384}{24.01}$

$g'=1.642$

The acceleration due to gravity on the moon is 1.642 m/s².

5 0

4 years ago

Read 2 more answers

Not sure need help

lord [1]

Answer:

Step-by-step explanation:

3-2i+8=23

5+2i+23

2i=18

i=-9

3 0

3 years ago