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ICE Princess25 [194]
3 years ago
11

If function g(x) = x2 + 2 is a transformation of the quadratic parent function, f(x) = x2, where is the y-intercept of function

g located?
Mathematics
2 answers:
Georgia [21]3 years ago
8 0

We have been given that function g(x)=x^2+2 is a transformation of the quadratic parent function f(x)=x^2. We are asked to find the y-intercept of function g.

We know that the function f(x)=x^2 is an upward opening parabola with vertex at point (0,0).

We know that vertex form of a parabola is in form y=a(x-h)^2+k, where point (h,k) represents vertex of parabola.

We can rewrite g(x) as:

g(x)=(x-0)^2+2

The vertex of the function g(x) is at point (0,2).

We know that the vertex of a function is the point, when x is equal to 0. Therefore, the y-intercept of the g is at (0,2).

Artemon [7]3 years ago
5 0

Answer:

Step-by-step explanation:

c

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