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2 years ago

Given the two points: (0,6) and (6,18), write the equation of the line.

1 answer:

4 0

Y=2x+6 We know the y intercept is +6 so we still can’t eliminate any of the options. We know it can’t be 1/3x or 1/2x because the y value is greater than the x value. (6)(2)+6=18

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Use the graph below to answer the question Y=-4(1/2)^x+2

EleoNora [17]

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3 years ago

Write the GCF. Then factor using the distributive property. Check your answer by applying the distributive property. 8 + 12

MrMuchimi

Answer:

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Step-by-step explanation:

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3 years ago

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prisoha [69]

Answer:

Step-by-step explanation:

The first term is 2

Therefor t₁ = 2

Each aditional term is 5 times the previous term

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3 years ago

Kelsey makes pendants that she would like to sell at an upcoming craft fair. She must pay $200 to rent a booth at the craft fair

lubasha [3.4K]

Answer:

Additional 26 pendants are to be sold to make profit.

Step-by-step explanation:

Rent of booth at the craft fair = $200

Cost of material for each pendant = $7.80

Let Kelsey makes $x$ number of pendants.

To calculate the total spending, we have to add the rent of booth at the craft fair and cost of material for $x$ number of pendants.

Cost of material for $x$ number of pendants = Cost of material for each pendant multiplied by number of pendants

Cost of material for $x$ number of pendants = $7.80 $\times$ $x$

So, total cost = $200 + $7.80 $\times$ $x$

Now, each pendant is sold at $13.50

So, total money made by selling $x$ pendants = $13.50 $\times$ $x$

For making profit, total money made must be greater than the total cost.

Therefore, the inequality becomes:

$\bold{13.50 \times x > 200+7.80\times x }$

Let us solve the inequality now:

$13.50x - 7.80x>200\\\Rightarrow 5.7x > 200\\\Rightarrow \bold{x > 35.08}$

So, at least 36 pendants are to be sold to make a profit.

Additional 36-10 = 26 pendants are to be sold to make profit.

5 0

3 years ago

In Argentina, a cow on a ranch is expected to need an average of 4200 m2

nika2105 [10]

The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.

And we are asked to find the total area of their grazing but in hectares. So, we can write:

$1 \: cow = 4200 \: {m}^{2}$

Then, for 4500 cows:

$4500 \: cows = 4200 \: {m}^{2} \times 4500$

$4500 \: cows = 18900000 \: m {}^{2}$

We know that, 1 hectares = 10000 m² = 10⁴ m²

Then let the area of the field be x in hectares:

$1 \: hectare = 10000 \: {m}^{2}$

$x \: hectare = 18900000 \: {m}^{2}$

Then, putting them in proportion, We will get:

$x = \dfrac{18900000}{10000} hectares$

$x = \boxed{ 1890 \: hectares}$

So, the total area in hectares = 1890 hectares.

And we are done !!

#CarryOnLearning

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6 0

3 years ago