Question

Please help: In Δ ABC, sin A=88, sin B=42, and a =17, find the length of b.

Answer 1

Answer:

11.4 units

Step-by-step explanation:

b/sinB = a/sinA

b/sin(42) = 17/sin(88)

b = sin(42) × 17/sin(88)

b = 11.38215401

Answer 2

Answer:

Step-by-step explanation:

Use the law of sines.

$\frac{sin A}{a} = \frac{sin B}{b}$

Plug values in.

$\frac{sin88}{17} = \frac{sin42}{b}$

Cross multiply.

$bsin88 = 17sin42\\b = 11.38$

Hope that helps.