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DaniilM [7]
3 years ago
11

You pick a card at random, put it back, and then pick another card at random. 2 3 4 5 What is the probability of picking a numbe

r greater than 3 and then picking a 4? Simplify your answer and write it as a fraction or whole number.
Mathematics
2 answers:
Phantasy [73]3 years ago
4 0
3/4 or i think its 75%
olga_2 [115]3 years ago
3 0

Answer:

3/4 or a 75% chance

Step-by-step explanation:

Out of 4 cards ( 2 3 4 5), here are the cards greater than 3: 4, and 5. That leaves you with a 2/4 chance of drawing one of them. (2 cards, 4 in total).

Then, picking a 4 out of 4 cards is a 1/4 chance; since that is one card out of 4 total possibilities.

1/4 + 2/4 = 3/4. Or, a 75% chance.

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Alchen [17]

The result is x^2 +x +4 -21/(x+3).

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Polynomial long division tends to be easier than numerical long division because the quotient term never needs adjustment. It is always the ratio of the highest degree terms of the dividend and divisor.

See the attachment for the intermediate steps.

7 0
3 years ago
Pand Q are points on the line<br> 3x + 2y = 6<br> (a)<br> Complete the coordinates of P and Q.
Mama L [17]

Answer:

you are multiplying baceicly

Step-by-step explanation:

3×2=6

3 0
3 years ago
Match the algebraic expression to the real life scenario
Anarel [89]

The Correct mathes are :

  • 1. x² - 4

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6 0
3 years ago
Can someone help please
Trava [24]

9514 1404 393

Answer:

  16.4

Step-by-step explanation:

The law of cosines is useful here. It tells you ...

  b^2 = a^2 + c^2 -2ac·cos(B)

  b^2 = 22^2 +10^2 -2·22·10·cos(44°)

  b^2 ≈ 267.49

  b ≈ √267.49 ≈ 16.35514

  b ≈ 16.4

4 0
3 years ago
The reliability of a piece of equipment is frequently defined to be the probability, P, that the equipment performs its intended
Sergio [31]

Answer:

a. y=1

b. Mean= 0.5; variance=0.5

c. In the first instance, the probability that p > 0.95 would mean that we are looking for the area of the rectangle with a height of 1 between 0.95 and 1, which implies it has length 0.05.

Therefore, the area is length × height, which is 0.05 ×1 = 0.05.

Second case, the probability that p is less than 0.95 would then be one minus the probability that p is greater than 0.95, so 1 - 0.05 = 0.95

D. a horizontal line at 20 between 0.90 and 0.95, and will be zero outside of this range.

Step-by-step explanation:

With the use of probability distribution, the probability that the equipment performs has a uniform distribution with minimum 0 and maximum 1.

a) The graph of the probability distribution will be 0 outside of the range of 0 to 1, so therefore y = 0. Inside the interval from 0 to 1, it will be constant (which is a horizontal line) with height 1÷(1-0) = 1, therefore y = 1.

b) The mean of the uniform is (maximum+minimum)/2.

Therefore, (1+0)/2 = 1/2 or 0.5.

The variance of the uniform is

(maximum-minimum)^2/12,

so (1-0)^2/12 = 1/12.

c) Since the probability distribution is rectangular, you can find probabilities by recalling the area of a rectangle which is: area = length × breadth.

In the first instance, the probability that p > 0.95 would mean that we are looking for the area of the rectangle with a height of 1 between 0.95 and 1, which implies it has length 0.05.

Therefore, the area is length × breadth, which is 0.05 ×1 = 0.05.

In the second case, the probability that p is less than 0.95 would then be one minus the probability that p is greater than 0.95, so 1 - 0.05 = 0.95.

d) If it is known that p is between 0.90 and 0.95, without the value, then we would assume that p has a uniform distribution between 0.90 and 0.95 since p originally had a uniform distribution.

In this case,

f(p) =

1/(0.95-0.90) = 20, 0.90 < p < 0.95,

0, otherwise.

In a nutshell, this function will have a horizontal line at 20 between 0.90 and 0.95, and will be zero outside of this range.

6 0
4 years ago
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