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joja [24]
3 years ago
6

How many solutions does h=(1/5)w+(8/5) have

Mathematics
1 answer:
Maru [420]3 years ago
7 0
Given that h=(1/5)w+(8/5), which is a straight line equation that takes the form y=ax+b, where a is the slope and b is the y-intercept. The equation has infinite number of solutions. The solutions are in the interval (-∞,∞).
The answer: Infinite soltuions
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What does the remainder tell you about the
tankabanditka [31]

Answer:

The remainder is the number left when you completely divide out your number to its max (Dividend = Divisor × Quotient + Remainder)

Step-by-step explanation:

I hope this helped

6 0
3 years ago
Brent checks the sales records for a random sample of 16 days and finds the mean number of gallons sold is 150 gallons per day;
Basile [38]

Answer:

[143.61, 156.39]

Step-by-step explanation:

Because the population standard deviation is not available AND the sample size is less than 31, we can use a t procedure here.

Plug these values into your calculator:

Sample mean = 150

Sample size = 16

Standard deviation = 12

Confidence level = 95% = 0.95

and get [143.61, 156.39] as your confidence interval

8 0
2 years ago
HELPPPPP!!!! ASAPPPPP!!!!!
kaheart [24]

Answer:

24

Step-by-step explanation:

XW=WY=12

If the opposite angle is 30, the hypotenuse is double the small side.

XZ=XW=2·12=24

5 0
3 years ago
1/2a - 1/2 = -3 solve the following equation
saul85 [17]

Answer:A= - 1/5

Step-by-step explanation:

8 0
3 years ago
Need help #3. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.
Sunny_sXe [5.5K]

Answer:

A

Step-by-step explanation:

We are given a right triangle with a base of <em>x</em> feet and a height of <em>h</em> feet, where <em>x</em> is constant and <em>h</em> changes with respect to time <em>t</em>.

The angle in radians is defined by:

\displaystyle \tan(\theta)=\frac{h}{x}

And we want to find the relationship that describes dθ/dt and dh/dt.

So, we will differentiate both sides with respect to <em>t</em> where <em>x</em> is a constant:

\displaystyle \frac{d}{dt}[\tan(\theta)]=\frac{d}{dt}\Big[\frac{h}{x}\Big]

Differentiate. Apply the chain rule on the left. Again, remember that <em>x</em> is just a constant, so we can move it outside the derivative operator. Therefore:

\displaystyle \sec^2(\theta)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}

Since we know that tan(θ)=h/x, <em>h</em> is the opposite side of our triangle and <em>x</em> is the adjacent. Therefore, by the Pythagorean Theorem, our hypotenuse will be:

\text{Hypotenuse}=\sqrt{h^2+x^2}

Since secant is the ratio of the hypotenuse to adjacent:

\displaystyle \sec(\theta)=\frac{\sqrt{h^2+x^2}}{x}

So:

\displaystyle \sec^2(\theta)=\frac{x^2+h^2}{x^2}

By substitution, we have:

\displaystyle \Big(\frac{x^2+h^2}{x^2}\Big)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}

By multiplying both sides by the reciprocal of the term on the left:

\displaystyle \frac{d\theta}{dt}=\frac{1}{x}\Big(\frac{x^2}{x^2+h^2}\Big)\frac{dh}{dt}

Therefore:

\displaystyle \frac{d\theta}{dt}=\frac{x}{x^2+h^2}\frac{dh}{dt}

Our answer is A.

3 0
3 years ago
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