Answer:
x=4
Step-by-step explanation:
6^x = 1296
Take the log base 6 on each side
log6(6^x) = log6(1296)
Rewrite 1296 as 6^4
x = log 6(6^4)
We know that log( a^b) = b log (a)
x = 4 log6(6)
We know that loga(a) =1
x = 4 *a
x =4
<h3>
<u>3</u><u>6</u> is the answer.</h3>
Step-by-step explanation:
Put value of b as given and using BODMAS rule,
Henve, value of of the given expression is 
C. f(x) = – 2 cos 6x + 1
Start by determining the amplitude. Since we've deduced the amplitude is 2, the equation can include either a positive or negative 2 (since amplitude measures absolute value).
Next is the period. The equation for period P is P = (2pi)/b. If P is pi/3, then
pi/3 = (2pi)/b. Thus your b value should be 6.
Finally, the midline would be given by + 1 since adding a unit shifts the function upwards. This means that instead of the highest y value being 2 and the lowest -2, instead you'd have values of 3 and -1.
(3 – 1)/2 = 1 (midpoint theory).
