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Zielflug [23.3K]
3 years ago
5

Is 5x-7+3x and 3x-7+5x equivalent

Mathematics
1 answer:
pychu [463]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

5x-7+3x =8x-7

3x-7+5x=8x-7

You might be interested in
Sara tried to evaluate 21 : 7 x 8 step-by-step
nlexa [21]

Answer: Sara multiplied by 3 when she should have multiplied by 8.

Step-by-step explanation:

21 : 7*8

7*8 = 56

21 : 56

The simplest form of this ratio is 3 : 8

6 0
3 years ago
Write an equation of a line in slope-intercept form that passes through the point (-2, 4) and has a slope of -3. (no spaces in y
mrs_skeptik [129]

Answer:

y = - 3x - 2

Step-by-step explanation:

Step 1:

y = mx + b     Slope Intercept Form

Step 2:

y = - 3x + b     Input Slope

Step 3:

4 = - 3 ( - 2 ) + b     Input x and y

Step 4:

4 = 6 + b     Multiply

Step 5:

- 2 = b       Subtract 6 on both sides

Answer:

y = - 3x - 2

Hope This Helps :)

8 0
3 years ago
The population of a city has been increasing by 2% annually. The sign shown is from the year 2000.
Fofino [41]

The population will be about 2972 population in 2020

<h3>Exponential functions </h3>

The standard exponential equation is expressed as;

y = ab^x

where

  • a is the intercept
  • b is the initial population
  • x is the time

Given the following parameters

  • a = 2000
  • b = 0.02

Substittute the given parameters into the formula

y = 2000(1.02)^x

If x = 20 (from 2000 to 2020)

The population will be expressed as;

y = 2000(1.02)^20

y = 2972 populations

Hence the population will be about 2972 population in 2020

Learn more on exponential functions here; brainly.com/question/12940982

5 0
3 years ago
(10 point's) 10 1/3 + 7/9 =
maks197457 [2]
10 1/3 = 10 3/9
3/9 + 7/9 = 1
10 + 1 = 11
Answer = 11
4 0
3 years ago
Solve the equation after making an appropriate substitution. X^6-98x^3=3375
Leni [432]
Rearrange x^6-98x^3=3375 to give

x^6-98x^3-3375=0

Let x^3 be a variable 'p' and so we can write x^6 as x^6=(x^3)(x^3)=(p)(p)= p^2

Rewrite the equation in terms of 'p'

p^2-98p-3375 = 0

where a=1, b=-98, c=-3375

using the quadratic formula \frac{-b+ \sqrt{b^2-4ac} }{2a} and subsitute the value of a, b, c

p_1= \frac{-(-98)+ \sqrt{(-98)^2-4(1)(-3375)} }{2} =125

p_2= \frac{-(-98)- \sqrt{(-98)^2-4(1)(-3375)} }{2} =-27

There are two value of p; 125 and -27 

Now we find the value of x

Earlier we substitute x^3 for p and x^6 for p^2

When p=125, x= \sqrt[3]{125}=5
When p = -27, x= \sqrt[3]{-27}=-3

So the final answer is the two values of x; 

x = 5 OR x = -3
3 0
3 years ago
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