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irinina [24]
3 years ago
6

Tricia has a birthday party. During the party, she opened 36 gifts, which was 60% of all her gifts. After the party, she opened

the rest of the gifts and found that 25% of them were the same present, so she returned all but one of the duplicate gifts. How many gifts did she return?
Mathematics
1 answer:
Reptile [31]3 years ago
8 0

Answer:

She returned 5 gifts.

Step-by-step explanation:

36 gifts is 60% = 0.6 of all the gifts that she received. How many presents are 100% = 1?

36 gifts - 0.6

x gifts - 1

0.6x = 36

x = 36/0.6

x = 60

She received 60 gifts.

She opened the rest of the gifts and found that 25% of them were the same present

The rest is 60 - 36 = 24 gifts.

25% is (1/4)*24 = 6 duplicate figts

She returned all but one of the duplicate gifts.

That is, she returned 6 - 1 = 5 gifts.

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When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0
3 years ago
Question 2 Please
NeX [460]

Answer:

Step-by-step explanation:

Start by moving the 3 to the other side of the equals sign to get

tan^2(2\theta)=3

tan^2(2\theta)=(tan(2\theta))(tan(2\theta)) so with that replacement:

(tan(2\theta))(tan(2\theta))=3

By the Zero Product Property,

tan(2\theta)=3 or tan(2\theta)=3

Yes these are both the same, so we only need one of them.  Once we find the angle, they are both the same, so we only need one of these equations.

If

tan(2\theta)=3, take the inverse tangent of both sides to give you:

2\theta=tan^{-1}(3) and

2\theta=71.565 so

\theta=35.8

Tangent increases in increments of pi or 180, so the other angle within the given interval is 35.8 + 180 = 215.8

6 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT
Annette [7]

The first answer is correct

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