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Flauer [41]
3 years ago
8

Could someone answer these 3 questions?

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

They are correct

Step-by-step explanation:


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Can someone explain if I am wrong?
snow_lady [41]

Answer:

Step-by-step explanation:

A. (b - 10)(b + 10) = 180

b^{2}-100 = 180

b^{2}= 280

b = \sqrt{280}

b = 2\sqrt{70}

Your A is correct.

B. 2\sqrt{70} - 10 = c

c = 6.733200531 = 6.73  Try rounding to 3 significant figures.

C. 2\sqrt{70} + 10 = d

d = 26.73320053 = 26.7

You are correct in all 3 answers. Perhaps you should try rounding to 3 significant figures for your c and d values.

I hope this helps!! ^-^

8 0
3 years ago
Read 2 more answers
The stem-and-leaf plot shows the distances, in miles, that a group of owners of new cars drove one weekend.
Slav-nsk [51]
The owners that drove between 50 and 65 miles are five owners.
5 0
4 years ago
given sin0= 2/3 and angle 0 is in quadrant 2, what is the exact value of cos0 in simplest form? simplify all radicals if needed
Kitty [74]

Answer: ( -\sqrt{5} / 3)

Step-by-step explanation:

sin(angle) = opposite/hypotenuse

opposite =2

hypotenuse = 3

solve for adjacent side with pythagorean theorum

opposite^2 + adjacent^2 = hypotenuse^2

2^2 + adjacent^2 = 3^2

4 + adjacent^2 = 9

adjacent^2 = 9 - 4

adjacent^2 = 5

adjacent = \sqrt{5}

-\sqrt{5} since it is in the second quadrant

cosx = (adjacent/hypotenuse)

cosx = (-\sqrt{5}/3)

(-\sqrt{5}/3)

4 0
2 years ago
Hellllpppppppppppppppppppp plz
nadya68 [22]

Answer:

It is an alternate angle

8 0
3 years ago
A right triangle has side length 9,40, and 41 as shown below.
Harrizon [31]

\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\\tan\theta=\dfrac{opposite}{adjacent}\\\\\text{We have}\\\\opposite=40\\adjacent=9\\hypotenuse=41\\\\\text{substitute}\\\\\tan M=\dfrac{40}{9}\\\\\sin M=\dfrac{40}{41}\\\\\cos M=\dfrac{9}{41}

4 0
3 years ago
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