Answer:
x = 2
Step-by-step explanation:
the equation of the line can be found using the slope intercept form
y = mx +b
y= -3/2 x + 3
x intercept is found by setting y=0 bc that will give you the x-value at which the line crosses the x -axis so
0 = -3/2x+3 (subtract the 3 on both sides) would cancel out the + 3 and would
-3 = -3/2 x (divide by -3/2 on both sides to cancel out the -3/2)
x = 2
X²=3x+3
x²-3x-3=0. have to get 0 on right first
identify a,b,c. a is 1, b is -3, c is -3
now plug in to the quadratic formula...
x = -b±√(b²-4*a*c) / 2a
x = -(-3) ± √((-3)²-4*1*(-3)) / (2*1)
x= 3 ± √(9- -12) / 2
x=( 3 ± √21) /2
A line that is parallel has the same slop where a line that is perpendicular has a slop that is negative and reciprocal.
so for the parallel one you don't need to worry about the slop because it will be 2/3x. But yous the point slope equation form
y-y1=m(x-x1)
y+5=2/3(x+2)
y+5=2/3x+ 4/3
y=2/3x-11/3
-2/3x+y=-11/3
multiple by -1 so A inst negative
2/3-y=11/3
For a line that is perpendicular you just need to flip the original 2/3x slope and make it negative.
y+5=-3/2(x+2)
y+5=-3/2x-3
y=-3/2x-8
3/2x+y=-8
163.2 is the correct Answer
