Answer:
I think it's 5
Step-by-step explanation:
The distance from point A to 0 is 2, then to point B makes it 3, then to point C is a total of 5. Or you could just add the absolute value of A, which is 2, with the absolute value of C, which is 3 to get 5
Answer:
3.6
Step-by-step explanation:
-7a+1.6a=-19.44
-5.4a=-19.44
5.4a=19.44
a=19.44/5.4
a=3.6
Answer:
B=10
Step-by-step explanation:
worked it out on a graph on the internet
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
B(-2,5)
Step-by-step explanation:
Hope that this is helpful.
Have a nice day.