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Pavlova-9 [17]
3 years ago
10

The segments shown below could form a triangle.

Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0

sorry i don,t unerstan what u wn,t

OlgaM077 [116]3 years ago
6 0
Tru Becuase you can match a to a b to b and c to c and it would form a triangle
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Someone plz help me I will give brainliest
Brut [27]

Answer:

$33.81

Step-by-step explanation:

Strawberries = $2.49 Per Pound (Bought 3)

Blueberries = $3.19 Per Pound (Bought 2)

Pineapples = $4.99 Per Pound (Bought 4)

So we have to multiply each price with the number of fruits bought.

So, For Example, Strawberries: <em>$</em><em>2</em><em>.</em><em>4</em><em>9</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>$</em><em>7</em><em>.</em><em>4</em><em>7</em>

After you did all three individually, add them all up.

Strawberries : <em>$</em><em>7</em><em>.</em><em>4</em><em>7</em>

Blueberries : <em>$</em><em>6</em><em>.</em><em>3</em><em>8</em>

Pineapple : <em>$</em><em>1</em><em>9</em><em>.</em><em>9</em><em>6</em>

<em>Total</em><em> </em><em>=</em><em> </em><em>$</em><em>3</em><em>3</em><em>.</em><em>8</em><em>1</em>

<h2><em>Hope</em><em> </em><em>This</em><em> </em><em>Helps</em><em>!</em></h2>
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Gina deposit $150 at the start of each year into a college savings account that pays 4% simple interest at the end of each year.
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An international polling agency estimates that 36 percent of adults from Country X were first married between the ages of 18 and
alukav5142 [94]

Answer:

(B) 0.2843

Step-by-step explanation:

Let d be the difference in proportions from Country X and Country Y who were first married between the ages of 18 and 32.

Then hypotheses are

H_{0}: d=0.15

H_{a}: d<0.15

Test statistic can be found using the equation

z=\frac{p1-p2-0.15}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of Country X (0.36)
  • p2 is the sample proportion of Country Y (0.26)
  • p is the pool proportion of p1 and p2 (\frac{60*0.36+50*0.26}{50+60}=0.31)
  • n1 is the sample size of adults from Country X (60)
  • n2 is the sample size of adults from Country Y (50)

Then z=\frac{0.36-0.26-0.15}{\sqrt{{0.31*0.69*(\frac{1}{60} +\frac{1}{50}) }}} ≈ 0.5646

p-value of test statistic is ≈ 0.2843

p-value states the probability that the difference in proportions between a random sample of 60 adults from Country X and a random sample of 50 adults from Country Y who were first married between the ages of 18 and 32 is at least 0.15

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