All categories

3 years ago

-3-(-2x) = -6 What’s X

Mathematics

1 answer:

vitfil [10]3 years ago

6 0

-3+2x = -6 (negative and negative changes to positive (+))

2x = -6+3

2x = -3

x = -3/2

You might be interested in

The length of a rectangle is represented by x+3 and the width by 2x-4. Write an expression for the area of this rectangle

madam [21]

Answer:

2x² +2x - 12

Step-by-step explanation:

area of rectangle = length X width

length = x+3

width = 2x - 4

Area = (x+3)(2x-4)

= x(2x-4) +3(2x-4)

= 2x² - 4x + 6x - 12

= 2x² +2x - 12

5 0

3 years ago

The areas of the two watch faces have a ratio of 16:25 What is the ratio of the radius of the smaller watch face to the radius o

Leona [35]

Answer:

The ratio of the radius of the smaller watch face to the radius of the larger watch face is 4:5.

Step-by-step explanation:

Let the Area of smaller watch face be $A_1$

Also Let the Area of Larger watch face be $A_2$

Also Let the radius of smaller watch face be $r_1$

Also Let the radius of Larger watch face be $r_2$

Now given:

$\frac{A_1}{A_2} =\frac{16}{25}$

We need to find the ratio of the radius of the smaller watch face to the radius of the larger watch face.

Solution:

Since the watch face is in circular form.

Then we can say that;

Area of the circle is equal 'π' times square of the radius 'r'.

framing in equation form we get;

$A_1 = \pi {r_1}^2$

$A_2 = \pi {r_2}^2$

So we get;

$\frac{A_1}{A_2}= \frac{\pi {r_1}^2}{\pi {r_2}^2}$

Substituting the value we get;

$\frac{16}{25}= \frac{\pi {r_1}^2}{\pi {r_2}^2}$

Now 'π' from numerator and denominator gets cancelled.

$\frac{16}{25}= \frac{{r_1}^2}{{r_2}^2}$

Now Taking square roots on both side we get;

$\sqrt{\frac{16}{25}}= \sqrt{\frac{{r_1}^2}{{r_2}^2}}\\\\\frac{4}{5}= \frac{r_1}{r_2}$

Hence the ratio of the radius of the smaller watch face to the radius of the larger watch face is 4:5.

7 0

3 years ago

Use a known maclaurin series to obtain the maclaurin series for the given function. f(x = 8x2 tan?1(7x3

11Alexandr11 [23.1K]

Going out on a limb here and guessing that the function is

$f(x)=8x^2\tan^{-1}(7x^3)$

Please correct me if this isn't the case.

Recall that

$\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^nx^{2n+1}}{2n+1}$

which converges for $|x|$ .

It follows that

$8x^2\tan^{-1}(7x^3)=8x^2\displaystyle\sum_{n\ge0}\frac{(-1)^n(7x^3)^{2n+1}}{2n+1}$
$=\displaystyle\sum_{n\ge0}\frac{56(-49)^nx^{6n+3}}{2n+1}$

6 0

3 years ago

Write the point from of the equation for a line that passes through (6,—1) with a slope of 2

Paraphin [41]

Answer:

y = 2x-13

Step-by-step explanation:

The equation for a line is

y = mx+b where m is the slope and b is the y intercept

y = 2x+b

We know a point so we have a y and an x, so we can solve for b

-1 = 2(6) +b

-1 =12+b

Subtract 12 from each side

-1-12 = 12-12+b

-13 =b

Substitute this into y = 2x+b

y = 2x-13

7 0

3 years ago

Read 2 more answers

Or the figure shown on the right, find m∠3 and m∠4.

ioda

Answer:

m<3=84

m<4=96

Step-by-step explanation:

180-43-41=96

180-96=84

4 0

3 years ago

Read 2 more answers