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3 years ago

Round the number 784,072 to the nearest hundred thousand

Mathematics

2 answers:

Zina [86]3 years ago

7 0

The answer to your problem is 800,000.

Ostrovityanka [42]3 years ago

6 0

It would be 800,000.

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List the ordered pairs in the equivalence relations produced by these partitions of {a, b, c, d, e, f, g}: a) {a,b},{c,d},{e,f,g

finlep [7]

Answer:

a) {a,b} , {c,d} , {e,f,g},{a , b } = {(a,a) (b,b) (a,b) (b,a)},{c , d } = {(c,c) (d,d) (c,d) (d , c) } ,{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f)(g,g)}

b) { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)

c) {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

Step-by-step explanation:

a) {a,b} , {c,d} , {e,f,g}

{a , b } = {(a,a) (b,b) (a,b) (b,a)}

{c , d } = {(c,c) (d,d) (c,d) (d , c) }

{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f) (g,g)}

b) {a} ,{b},{c,d} ,{e,f},{g}

{ (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)}

c) {a,b,c,d},{e,f,g}

{(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

4 0

3 years ago

Write 24 as a product of its prime factors.

Alex777 [14]

prime factors are prime numbers that can be multiplied to give the number.
to find the prime factors the number is divided by the prime numbers by which the number is divisible.

24 / 3 = 8
8 / 2 = 4
4 / 2 = 2
2 / 2 = 1
24 is divisible by 3 , 2 , 2 and 2.
therefore 24 written as a product of its prime factors is 24 = 2 x 2 x 2 x 3

8 0

4 years ago

Read 2 more answers

Solve the world problem. the formula d = rt gives the distance traveled in time t at rate r. if a bicyclist rides for 2.3 hours

Marta_Voda [28]

Hello!

The answer to your question is D. 17.83 because 41 divided by 2.3 is equal to the answer and you are trying to solve for r.

4 0

3 years ago

1) -24, -4, 16, 36, ... Find a23

viktelen [127]

We're given the Arithmetic Progression -24, -4, 16, 36 ... .

We know that a term in an AP is generally represented as:

$\bf a_n\ =\ a\ +\ (n\ -\ 1)d$

where,

a = the first term in the sequence
n = the number of the term/number of terms
d = difference between two terms

We need to find $\sf a_2_3$ .

From the given progression, we have:

a = -24
n = 23
d = (-24 - (-4) = -20

Using these in the formula,

$\sf a_2_3\ =\ a\ +\ (n\ -\ 1)d\\\\\\a_2_3\ =\ -24\ +\ (23\ -\ 1)\ \times\ (-20)\\\\\\a_2_3\ =\ -24\ +\ 22\ \times (-20)\\\\\\a_2_3\ =\ -24\ -\ 440\\\\\\\bf a_2_3\ =\ -464$

Therefore, the 23rd term in the AP is -464.

Hope it helps. :)

7 0

3 years ago

S(t)=9t-4, find S(4)

melamori03 [73]

For this problem, you need to substitute 4 in for your variable t. the original equation is S(t) and the one you need is S(4) -- in other words, evaluate this equation when t = 4.

S(4) = 9(4) - 4
S(4) = 36 - 4
S(4) = 32 is your answer.

3 0

3 years ago